Solutions manual for Giancoli Physics, principles with applications
Then P = IV = (2.9 x 10aquot;2 A/m2) (0.1 m) (2ir) (10aquot;5 m) (30 x 10aquot;3 V) = 5.4 x 10aquot;9 W where we used Area = 2irrL. Chapter 16 1 In series, R = R1 + R2 103.
| Title | : | Solutions manual for Giancoli Physics, principles with applications |
| Author | : | Keith H. Brown |
| Publisher | : | - 1980 |
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